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What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve

0 x- 4+15
x--74 NE
x= -7 and x = -2
x= -1 and x = 4

User Geoffrey H
by
8.7k points

1 Answer

4 votes

Answer:

x=−41/20

Explanation:

(2x+3)(2)+8(2x+3)+11=0

Step 1: Simplify both sides of the equation.

(2x+3)(2)+8(2x+3)+11=0

(2x)(2)+(3)(2)+(8)(2x)+(8)(3)+11=0(Distribute)

4x+6+16x+24+11=0

(4x+16x)+(6+24+11)=0(Combine Like Terms)

20x+41=0

20x+41=0

Step 2: Subtract 41 from both sides.

20x+41−41=0−41

20x=−41

Step 3: Divide both sides by 20.

20x/20=−41/20

x=−41/20

User Alexkelbo
by
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