154k views
5 votes
Sec[sin-1 square root of 3 over 2]

User Shinnok
by
8.1k points

1 Answer

6 votes

Answer: √3/2

Explanation:

Sin[sin⁻¹ (√3/2)]

sin⁻¹ (√3/2 = 60°

60° is the acute angle, in the first quadrant

Therefore;

Sin[sin⁻¹ (√3/2)] = sin 60° ; since sin⁻¹ (√3/2 = 60°

Sin 60° = √3/2

Therefore, the answer = √3/2

User Roel Spilker
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories