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What is the molarity of 4 g of NaCl in 3,800 mL of solution?
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What is the molarity of 4 g of NaCl in 3,800 mL of solution?

User Dean Whitehouse
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1 Answer

10 votes

Answer:

.018 M

Step-by-step explanation:

Mole weight of NaCl (from periodic chart) = 58.44 g /mole

4 g / 58.44 gm/mole = .06845 mole

.06845 mole / (3.8 liter ) = .018 M

User CGK
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