Question

Find the maximum and minimum values of the function
f(x)= x^3-3x , x∈{-2,2}

Answer 1

x^3 -3x = 0

Take the derivative

f'(x) = 3x^2 -3 = 0

Solving by quadratic formula

Maximum at x = -1 and

Minimum at x = +1

Explanation: