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Find the maximum and minimum values of the function
f(x)= x^3-3x , x∈{-2,2}

User Brent
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1 Answer

5 votes

Answer:

x^3 -3x = 0

Take the derivative

f'(x) = 3x^2 -3 = 0

Solving by quadratic formula

Maximum at x = -1 and

Minimum at x = +1

Explanation:

User Bhavesh N
by
3.9k points