Question

F(x)=(x^5+5)^1/3, find f^-1 (x)

Answer 1

5√(x^1/3-5)

Explanation:

hey!

f(x)=(x^5 +5)^1/3

let f(x) be y

y=(x^5 +5)^1/3

now, interchanging x and y

or, x=(y^5 +5)^1/3

or, ∛x= y^5 + 5

or, x^1/3-5=y^5

or, y=5√(x^1/3-5)

therefore f^-1=5√(x^1/3-5)

hope it helps!

thank u!