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What are the roots of f(x) = x2 – 48?
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What are the roots of f(x) = x2 – 48?

User Meziane
by
3.9k points

2 Answers

4 votes

Answer:

If you mean x-intercepts and your equation is x^2 -48 then the roots are +6.928 and -6.928

User UnknownGosu
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3.8k points
4 votes

Answer:

(x +sqrt(48)) (x-sqrt(48))

Explanation:

sqrt = Square Root

sqrt(48) = 6.928

User Alex Hall
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4.0k points
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