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How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL
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1 vote
How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL

User Kutomer
by
5.6k points

2 Answers

3 votes

Answer:

1.07ML

Step-by-step explanation:

User Laurens Holst
by
6.4k points
4 votes

Answer:

Moles= 1.07mol

Step-by-step explanation:

C= 8.59M, V= 0.125dm3

n= C×V

n= 8.59×0.125= 1.07mol

User Charl
by
5.7k points
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