How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL

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asked Jan 27, 2021 179k views

1 vote

How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL

Chemistry
college

Kutomer asked

by Kutomer

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2 Answers

3 votes

Answer:

1.07ML

Step-by-step explanation:

Laurens Holst answered Jan 28, 2021

by Laurens Holst

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4 votes

Answer:

Moles= 1.07mol

Step-by-step explanation:

C= 8.59M, V= 0.125dm3

n= C×V

n= 8.59×0.125= 1.07mol

Charl answered Feb 1, 2021

by Charl

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