77.7k views
18 votes
Can someone help me with this?​

Can someone help me with this?​-example-1

2 Answers

13 votes

Answer:

30°

Step-by-step explanation:

∠LMP + ∠PMN = 180°

[∠LMO + ∠OMP] + [∠PMR + ∠RMN] = 180°

FIND x

(x - 10) + (x + 30) + x + 40 = 180

3x - 10 + 30 + 40 = 180

3x + 60 = 180

3x = 120

x =40

FIND ∠LMO

∠LMO = x - 10

∠LMO = (40) - 10

∠LMO = 30°

Hope this helps and God bless!

User Tenshi
by
7.3k points
7 votes

Answer:

∠LMO = 30°

Step-by-step explanation:

Angles on a straight line add up to 180°

⇒ (x - 10)° + (x + 30)° + 40° + x° = 180°

⇒ x° + x° + x° - 10° + 30° + 40° = 180°

⇒ 3x° + 60° = 180°

⇒ 3x° = 120°

⇒ x = 40

Substitute found value of x into the expression for ∠LMO:

⇒ ∠LMO = (40 - 10)°

⇒ ∠LMO = 30°

User Somar
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories