Question

Suppose a normal distribution has a mean of 79 and a standard deviation of 7. what is P(x>72)

Answer 1

Answer:it's .1587 round to .16 js took the test

Explanation:

Answer 2

X~N(72,5). Define Z=X−725

⇒

Z~N(0,1)

Now, P(67<X<72)=P(67−725<X−725<72−725)

=P(−1<Z<0)

=P(Z<0)−P(Z<−1)

=0.5−0.15866

=0.34134

Hence, the required probability is 0.34

*Hope it helps*