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Between x=2 and x=3 which function has a greater average rate of change than y=1/3^-x

A)y=2^x
B)y=5^x-2
C)y=1/4^-x
D)y=2/3^-x

User Vectoria
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1 Answer

7 votes

Answer:

C) y = (1/4)^(-x)

Explanation:

The average rate of change on an interval [a, b] is found using the formula ...

arc = (f(b) -f(a))/(b -a)

For an exponential function with base b on interval [2, 3], the rate of change is ...

arc = (b^3 -b^2)/(3 -2) = b^2(b -1)

This expression assumes a positive sign on the exponent.

We can compute the arc for each answer choice as ...

(reference) 1/3^-x = 3^x ⇒ arc = 3²(3 -1) = 18

A) 2^x ⇒ arc = 2²(2 -1) = 4

B) 5^(x-2) = (1/25)5^x ⇒ arc = (1/25)(5²)(5 -1) = 4

C) 1/4^-x = 4^x ⇒ arc = 4²(4 -1) = 48

D) (2/3)^-x = (3/2)^x ⇒ arc = (3/2)²(3/2 -1) = 9/8

An average rate of change greater than 18 is demonstrated by (1/4)^-x.

User DisneylandSC
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