Question

The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bending component due to load P, σbend, P, an axial component due to load Q, σaxial, Q, and a bending component due to load Q, σbend, Q. Calculate σaxial, P and σbend,P. Use the sign convention for normal stresses. If a normal stress component is tension, it is positive, and if it is compression, it is negative.

Answer 1

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

αbend,p = 19.648 ksi ( tensile )

Step-by-step explanation:

αaxial, p =
`(-p)/(A)` equation 1

αbend, p =
`((P*A)*(d)/(2) )/(I_(z) )` equation 2

P = load = 35 kips

A = area of column = 5.8
`in^(2)`

d = column cross section depth = 9.5 in

`I_(Z)` = 55.0
`in^(4)`

Hence equation 1 becomes

αaxial,p = -35 / 5.8 = - 6.034 ksi ( compressive )

equation 2 becomes

αbend, p =
`((35*6.5)((9.2)/(2)) )/(55)` = + 19.648 ksi ( tensile )