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How many moles of MgCl2 will be produced from 65.0 g of Mg(OH) assuming HCl is available in excess

User Thepanuto
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1 Answer

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Answer:

i guess the formula is Mg(OH)2 then the explanation is

Step-by-step explanation:

1.12 moles of MgCl₂

Step-by-step explanation:

Given parameters:

Mass of Mg(OH)₂ = 65g

Unknown:

Number of moles of MgCl₂ = ?

Solution:

To solve this problem, obtain a balanced reaction equation first;

Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O

From the reaction above, this is a typical neutralization process in which an acid reacts with a base to produce salt and water only.

Let's proceed; the reactant in excess is the HCl, acid. The other reactant is the Mg(OH)₂ and it must be the limiting reactant. A limiting reactant is one that is given in short supply and determines the extent of the reaction.

Find the number of moles of Mg(OH)₂;

Number of moles =

Molar mass of Mg(OH)₂ = 24 + 2(16 + 1) = 58g/mol

Number of moles = = 1.12moles

The balanced reaction equation shows that;

1 mole of Mg(OH)₂ gives 1 mole of MgCl₂

1.12 mole of Mg(OH)₂ will produce 1.12 moles of MgCl₂

User HuangJie
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