Question

Find the zero of picture is included

Answer 1

x = -12/6 = -2

x = -18/6 = -3

Explanation:

The zeros in an equation is the same thing as the x's.

3x²+15x+18 = 0 (Where a = 3, b = 15, c = 18)

One thing you could do to find the answer is use the quadratic formula:

x = (-b ± √(b²-4ac))/2a =

(-15 ± √15² - (4*3*18))/2*3 =

(-15 ± √225 - 216)/6 =

(-15 ± √9)/6 =

(-15 ± 3) / 6.

To find the first x we need to do (-15 + 3) / 6 and to find the second x we need to do (-15-3) / 6.

x = -12/6 = -2

x = -18/6 = -3

Answer 2

To find the zeros of the quadratic equation 3x^2 + 15x + 18 = 0, use the quadratic formula to obtain the values of x.

To find the zeros of the quadratic equation 3x^2 + 15x + 18 = 0, we can use the quadratic formula.

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± sqrt(b^2 - 4ac)) / (2a)

Plugging in the values from our equation, we get:

x = (-15 ± sqrt(15^2 - 4*3*18)) / (2*3)

After evaluating the expression, we find that the zeros of the equation are x = -3 and x = -2.

The probable question may be:

find the zero of 3x^2+15x+18=0 using any method.