Question

What is the perimeter, to the nearest hundredth of a unit, of the the

following polygon with vertices (-3, 2), (1, 2), (3,-1),(0,-3), (-4, -3)?

Answer 1

20.31 units to the nearest hundredth.

Explanation:

We need to use the distance formula between the points and find their sum.

D1 = √((2-2^2 + (1+3)^2) = √16 = 4

D2 = √(-1-2)^2 + (3-1)^2) = √13

D3 = √(-3+1)^2 + (0-3)^2) = √13

D4 = √(-3+3)^2 + (-4)^2) = √16 = 4.

D5 = √(-3-2)^2 + (-4+3)^2) = √26.

Perimeter = D1+D2+D3+D4+D5

= 4+√13+√13 + 4 +√26

= 20.31 units.