Question

The triangle on the grid will be translated two units left. On a coordinate plane, triangle A B C has points (negative 1, negative 1), (negative 1, negative 5), (0.5, negative 5). Which shows the triangle when it is translated two units left? On a coordinate plane, triangle A prime B prime C prime has points (1, negative 1), (1, negative 5), (2.5, negative 5). On a coordinate plane, triangle A prime B prime C prime has points (negative 3, negative 1), (negative 3, negative 5), (negative 1.5, negative 5). On a coordinate plane, triangle A prime B prime C prime has points (negative 1, 1), (negative 1, negative 3), (0.5, negative 3). On a coordinate plane, triangle A prime B prime C prime has points (negative 1, negative 3), (negative 1, negative 7), (0.5, negative 7) hurry please its timed ;-;

Answer 1

the answer is B

Explanation:

I don't give explanations all you want is the answer

Answer 2

Option B.

Explanation:

The given vertices of triangle ABC are (-1, -1), (-1, -5) and (0.5, -5).

We need to find the coordinates of triangle when it is translated two units left.

So, the rule of translation is

`(x,y)\rightarrow (x-2,y)`

Using this rule, we get

`A(-1,-1)\rightarrow A'(-1-2,-1)=A'(-3,-1)`

`B(-1,-5)\rightarrow B'(-1-2,-5)=B'(-3,-5)`

`C(0.5,-5)\rightarrow C'(0.5-2,-5)=C'(-1.5,-5)`

The vertices of triangle A'B'C' are A'(-3,-1), B'(-3,-5) and C'(-1.5,-5).

Therefore, the correct option is B.