How many atoms are present in 179.0 g of iridium? include units please:)!

asked May 9, 2021 31.5k views

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How many atoms are present in 179.0 g of iridium?
include units please:)!

by Dragi

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Answer:

A. 5.606x10²³atoms

Step-by-step explanation:

Shayan Moghadam answered May 12, 2021

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Answer:

179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium

Step-by-step explanation:

Uingtea answered May 12, 2021

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