Answer:
496.24 KPa
Step-by-step explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 102.3 KPa
Initial temperature (T1) = 45.5°C = 45.5°C + 273 = 318.5K
Initial volume (V1) = 12.5L
Final volume (V2) = 2.50L
Final temperature (T2) = 36.0°C = 36.0°C + 273 = 309K
Final pressure (P2) =?
Step 2:
Determination of the pressure in the chamber.
The final pressure i.e the pressure of the chamber can be obtained by using the general gas equation as follow:
P1V1/T1 = P2V2/T2
102.3 x 12.5/318.5 = P2 x 2.5/309
Cross multiply to express in linear form
318.5 x 2.5 x P2 = 102.3 x 12.5 x 309
Divide both side by (318.5 x 2.5)
P2 = (102.3 x 12.5 x 309)/(318.5x2.5)
P2 = 496.24 KPa
Therefore, the pressure in the chamber is 496.24 KPa