Question

What is the molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate, Na2SO4?

0.007 mol/L
0.07 mol/L
0.0007 mol/L
0.7 mol/l

Answer 1

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7
`(moles)/(liter)`

Step-by-step explanation:

Molarity is a concentration measure that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So, the Molarity of a solution is determined by the expression:

`Molarity (M)=(number of moles of solute)/(volume)`

Molarity is expressed in units (
`(moles)/(liter)`).

In this case:

• number of moles= 0.0350

• Volume=50 mL=0.05 L (1 L= 1,000 mL)

Replacing:

`Molarity=(0.0350 moles)/(0.05 L)`

Molarity= 0.7
`(moles)/(liter)`

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7
`(moles)/(liter)`