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Weather balloon is filled with 62.3 L of helium gas at 760 mm of Hg after being released the volume increases to 130 L as the balloon rises, what is the pressure at this new altitude?

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Answer : The pressure at this new altitude is, 364.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.


P\propto (1)/(V)

or,


P_1V_1=P_2V_2

where,


P_1 = initial pressure = 760 mmHg


P_2 = final pressure = ?


V_1 = initial volume = 62.3 L


V_2 = final volume = 130 L

Now put all the given values in the above equation, we get:


760mmHg* 62.3L=P_2* 130L


P_2=364.2mmHg

Thus, the pressure at this new altitude is, 364.2 mmHg

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