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Write a vector equation of the line that passes through point P(-4,11) and is parallel to a=[-3,8]. Then write parametric equations of the line.

User Afuc Func
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1 Answer

7 votes

Answer:


\vec l = (-4, 11) + t\cdot (-3,8),
x = -4 - 3\cdot t and
y = 11 + 8\cdot t

Explanation:

The vector equation of the line is:


\vec l = \vec P + t \cdot \vec A


\vec l = (-4, 11) + t\cdot (-3,8)

The parametric equations of the line are:


x = -4 - 3\cdot t and
y = 11 + 8\cdot t

User Lasitha Lakmal
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