Answer:
See the answer below
Step-by-step explanation:
Free hanging ear lobe's allele = E
Attached ear lobe's allele = e
E is dominant over e.
- A heterozygous person with Ee genotype will produce E and e egg/sperm during gametogenesis.
E gamete = 50%
e gamete = 50%
2. A man and a woman both heterozygous for earlobe
Ee x Ee
Offspring = EE, 2Ee, ee
Probability of a child having free ear lobe = 3/4
Probability of a child having attached earlobe = 1/4
3. A man attached ear lobe with a woman with free earlobe produced three children out of which two have free earlobes and one has attached ear lobes.
Genotype of man with attached earlobe = ee
Genotype of woman with free earlobes = Ee (since they produced both free and attached earlobe children)
ee x Ee
Genotype of children = Ee, ee, Ee and ee
Ee = free earlobes
ee = attached earlobe