Question

What is the magnitude of the electric field produced by a charge of magnitude 5.00 μC at a distance of 2.00 m?

Answer 1

See answer below

Step-by-step explanation:

Hi there,

To find the magnitude of electric field from a single charge, the following formula is used:

`E=k (q)/(r^2)` where q is the charge in Coulombs (C), and r is the distance from the center of the charge in metres (m). k is the constant:

`k= 8.99*10^(9)`
`N*m^2/C^2`

Put q in C: q=5.00*10^(-6)

Plug in values:

`E=(8.99*10^(9) )(5.00*10^(-6) )/((2.00)^2) N/C`

`E = 1.124*10^(4) N/C`