Question

A charged particle is placed in a uniform magnetic field and negligible gravitational field. When released it will exhibit constant

Answer 1

Constant velocity

Step-by-step explanation:

The Lorentz force acting on the particle is given by F = Bqvsinθ where B = magnetic field strength, q = charge, v = speed of charge and θ = angle between v and B.

If the charge is released with a velocity, v, it experiences a force, F = Bqvsinθ. Since F = ma, Bqvsinθ = ma and a = Bqvsinθ/m. So, since all the variables are constant, the charged particle exhibits no acceleration since the velocity is constant.