Question

3.00 L of Ch4 is known to contain 0.650 moles at a certain temperature and pressure if the volume of a chamber of CH4 increased from 7.00L to 8.20 L how many moles CH4 were added assume temperature and pressure stayed constant

Answer 1

Answer: 0.111 moles of
`CH_4` were added

Step-by-step explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

`V\propto n`

or,

`(V_1)/(V_2)=(n_1)/(n_2)`

where,

`V_1` = initial volume of gas = 7.00 L

`V_2` = final volume of gas = 8.20 L

`n_1` = initial moles of gas = 0.650 mole

`n_2` = final moles of gas = ?

Now we put all the given values in this formula, we get

`(7.00)/(8.20)=(0.650)/(n_2)`

`n_2=0.761`

Thus moles added are (0.761-0.650) = 0.111 moles