Answer:
![\bar X = (Lower +Upper)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qf0bb1w3jptd4n7vcnoq54yw82jdudiub4.png)
![\bar X= (1.9+3.3)/(2)= 2.6](https://img.qammunity.org/2021/formulas/mathematics/high-school/vz7y4t6ipod09gos3u7s5y1fk4fjedcnf9.png)
And the margin of error with this one:
![\bar X = (Upper-Lower)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vdbp4cl80l3gm4gatclqyel65fkw2h272q.png)
![ME = (3.3-1.9)/(2)= 0.7](https://img.qammunity.org/2021/formulas/mathematics/high-school/px9wso78n21en7oeia0n9z4lobh0khtezx.png)
Explanation:
Assuming that the parameter of interest is the sample mean
. And we can estimate this parameter with a confidence interval given by this formula:
(1)
For this case the confidence interval is given by (1.9, 3.3)
Since the confidence interval is symmetrical we can estimate the sample mean with this formula:
![\bar X = (Lower +Upper)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qf0bb1w3jptd4n7vcnoq54yw82jdudiub4.png)
![\bar X= (1.9+3.3)/(2)= 2.6](https://img.qammunity.org/2021/formulas/mathematics/high-school/vz7y4t6ipod09gos3u7s5y1fk4fjedcnf9.png)
And the margin of error with this one:
![\bar X = (Upper-Lower)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vdbp4cl80l3gm4gatclqyel65fkw2h272q.png)
![ME = (3.3-1.9)/(2)= 0.7](https://img.qammunity.org/2021/formulas/mathematics/high-school/px9wso78n21en7oeia0n9z4lobh0khtezx.png)