Answer:
we are given the 3-methyl2 butanone and upon the reduction with LiAIH4 there is formed alcohol, there are two possible side attack,
- from the back side
- from the front side.
therefore, whenever the front side attacks then the -CH3 moves back the plain and the H will be above the plane. More so, when attack from the back side the H moves below the plane and -CH3 moves above the plane. -OH is evident in the plane. see the attachment below to view the structure.
Step-by-step explanation: