Question

A bag contains 2 yellow marbles and 5 red marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is red and the second one is yellow?

Answer 1

The probability of drawing a red marble first and a yellow marble second is 5/21.

Step-by-step explanation:

To find the probability that the first marble drawn is red and the second one is yellow, we need to consider the total number of marbles and the number of red and yellow marbles in the bag.

Since we are drawing without replacement, the probabilities are dependent.

The probability of drawing a red marble on the first draw is 5/7. After the first marble is drawn, there are now 4 red marbles and 2 yellow marbles left in the bag. The probability of drawing a yellow marble on the second draw is 2/6.

Therefore, the probability of drawing a red marble first and a yellow marble second is (5/7) × (2/6) = 10/42 = 5/21.

Answer 2

Number of red balls = 5 Number of orange balls = 2

Number of yellow balls = 1

Number of green balls = 2

Therefore total number of balls = 10.

Probability of getting a ball = P(choosing orange ball) = After picking an orange ball, we are left with 9 ballsP ( choosing a green ball) = P(choosing an orange marble and a green marble) = 0.04444 is the approximate probability of choosing an orange marble and a green marble.

Step-by-step explanation: