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The rovibrational transition of 1H 35Cl with v = 0 to 1, J = 11 to 10 occurs at 2757.89 cm-1 , and the transition with v = 0 to 1, J = 10 to 9 occurs at 2779.07 cm-1 . From this information, i) calculate the spring constant of the vibrational potential (assuming the harmonic approximation and rigid rotor approximation) and ii) the equilibrium length of the HCl bond.

User Xeye
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The rovibrational transition of 1H 35Cl with v = 0 to 1, J = 11 to 10 occurs at 2757.89 cm-example-1
The rovibrational transition of 1H 35Cl with v = 0 to 1, J = 11 to 10 occurs at 2757.89 cm-example-2
User Kenisha
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