Question

What is the mole fraction of NaCl in a mixture containing 7.21 moles NaCl, 9.37 moles KCL, and 3.42

moles LiCI?

Answer 1

.36

Step-by-step explanation:

Answer 2

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of
`NaCl` = 7.21 mole

Moles of
`KCl` = 9.37 mole

Moles of
`LiCl` = 3.42 mole

Now we have to calculate the mole fraction of
`NaCl`.

`\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}`

Now put all the given values in this formula, we get:

`\text{Mole fraction of }NaCl=(7.21)/(7.21+9.37+3.42)=0.360`

Therefore, the mole fraction of NaCl in a mixture is, 0.360