Question

For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:

3 N2H4 (l)

⟶

4 NH3(g) + N2(g)

Answer 1

Answer : The moles of
`NH_3` formed are, 22.3 moles.

Explanation : Given,

Moles of
`N_2H_4` = 16.72 mol

The given chemical reaction is:

`3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)`

From the balanced chemical reaction, we conclude that:

As, 3 moles of
`N_2H_4` react to give 4 moles of
`NH_3`

So, 16.72 moles of
`N_2H_4` react to give
`(4)/(3)* 16.72=22.3` moles of
`NH_3`

Therefore, the moles of
`NH_3` formed are, 22.3 moles.