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3. A rock is thrown from the top of a tall building. The distance, in feet, between the rock and the ground t seconds after it is thrown is given by d(t) = -16t^2 - 4t + 382. How long after the rock is
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3. A rock is thrown from the top of a tall building. The distance, in feet, between

the rock and the ground t seconds after it is thrown is given by d(t) = -16t^2 - 4t
+ 382. How long after the rock is thrown is it 370 feet from the ground? *

User Slabounty
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Answer:

Explanation:

3. A rock is thrown from the top of a tall building. The distance, in feet, between-example-1
User Ozy
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User Dunni
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D=-16t^2-4t+382 help plz
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