Question

(02.02)

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)
Select one
O a. No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y
b. No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y
c. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48
d. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24

Answer 1

Let

L--------> the length of the rectangle

y------> the width of the rectangle

x------> the perimeter of the rectangle

we know that

The perimeter of the rectangle is equal to

In this problem we have

For a width

Find the value of the perimeter

so

therefore

the answer is the option A

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y. .