Answer:
The resulting UCL value for the line is 0.07. The right answer is d
Step-by-step explanation:
According to the given data we have the following:
P-bar = Fraction defective = 0.05
Sp = Standard deviation = 0.01
In order to calculate the resulting UCL value for the line we have to use the following formula:
UCL = P-bar + (Z x Sp)
Using standard normal table, for 95% confidence level Z=1.96
Therefore, UCL = 0.05 +(1.96x0.01)=
UCL = 0.0696, Hence UCL=0.07
The resulting UCL value for the line is 0.07