Question

Tina has a sample of gaseous water at a temperature of 400 C

and a pressure of 4 atm.
If Tina increases the pressure to 200 atm, will the gaseous water
liquefy? Why or why not?

Answer 1

The gaseous water will not liquefy since its new temperature is far higher that its initial temperature.

Step-by-step explanation:

To know if the gaseous water will liquefy or not, we must first obtain the new temperature of the water. This can be obtained as follow:

Step 1:

Data obtained from the question:

Initial temperature (T1) = 400°C

Initial pressure (P1) = 4 atm

Final pressure (P2) = 200 atm

Final temperature (T2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 400°C = 400°C + 273 = 673K

Step 3:

Determination of the final temperature of the water.

Using the equation P1/T1 = P2/T2, the final temperature can obtain as follow:

P1/T1 = P2/T2

4/673 = 200/T2

Cross multiply to express in linear form

4 x T2 = 673 x 200

Divide both side by 4

T2 = (673 x 200) /4

T2 = 33650K

The final temperature of sample of gaseous water is 33650K

Step 4:

Conversion of Kelvin temperature to celsius temperature.

Temperature (celsius) = temperature (Kelvin) - 273

Temperature (celsius) = 33650K - 273

Temperature (celsius) = 33377°C

Therefore, the sample of the gaseous water will not liquefy since its new temperature is far higher that its initial temperature.