Question

A silver block, initially at 55.6∘C, is submerged into 100.0 g of water at 24.5∘C in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.3∘C. The specific heat capacities for water and silver are Cs,water=4.18J/(g⋅∘C) and Cs,silver=0.235J/(g⋅∘C).

What is the mass of the Silver block?

Answer 1

`m_(Ag) = 175.987\,g`

Step-by-step explanation:

The First Law of Thermodynamics helps to determine the mass of the silver block:

`m_(Ag)\cdot \left(0.235\,(J)/(g\cdot ^(\textdegree)C) \right)\cdot (55.6^(\textdegree)-27.3^(\textdegree)C) = (100\,g)\cdot \left(4.18\,(J)/(g\cdot ^(\textdegree)C) \right)\cdot (27.3^(\textdegree)C-24.5^(\textdegree)C)`

The mass of the silver block is:

`m_(Ag) = 175.987\,g`