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The slender 15 kg bar is initially at rest and standing in the vertical position when the bottom end A is displaced slightly to the right. If the track in which it moves is smooth, determine the speed at which end A strikes the corner D. The bar is constrained to move in the vertical plane. Neglect the mass of the cord BC.

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Answer:

Step-by-step explanation:

Given Parameters

Mass of slender, m = 15kg

Length of AB, a = 4.5m

Initial velocity of slender,
v_1 = 0m/s

we draw the initial condition of slender as shown in the attached file 1

Now consider the instantaneous center at C

Write the expression to calculate the kinetic energy at initial position (
K.E_1)


K.E_1 = (1)/(2)m{v_1}^2

substitute the values in the above expression


K.E_1 = 0

Write the expression to calculate the Potential energy at initial position (
P.E_1)


P.E_1 = mgh_1

here,
h_1((4.5)/(2)) is the position of the center of mass in initial position

Substitute the values in the above expression


P.E_1 = 15 * 9.81 * (4.5)/(2)

= 331.088Nm

the condition of the slender at the final position is as shown in the second file attached

check other files for extra details

The slender 15 kg bar is initially at rest and standing in the vertical position when-example-1
The slender 15 kg bar is initially at rest and standing in the vertical position when-example-2
The slender 15 kg bar is initially at rest and standing in the vertical position when-example-3
The slender 15 kg bar is initially at rest and standing in the vertical position when-example-4
The slender 15 kg bar is initially at rest and standing in the vertical position when-example-5
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