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How much heat energy, in joules, is released to your body after you drink a cup of hot tea containing 125g of water that is cooled from 55℃ to a body temperature at 37℃ (water has a specific heat capacity of 4.184 J/g℃

2 Answers

3 votes

Answer:


Q=-9414J

Step-by-step explanation:

Hello,

In this case, the released heat by the water in this heating process is defined in terms of its mass, heat capacity and temperature difference as shown below:


Q=mCp\Delta T

Thus, with the given data indicating that water was at 55 °C before entering the body, we obtain:


Q=125g*4.184(J)/(g^oC)*(37-55)^oC


Q=-9414J

Such negative result means that the water releases that amount of heat to the body.

Best regards.

User RollingInTheDeep
by
5.7k points
7 votes

Answer:


Q_(out) = 9414\,J

Step-by-step explanation:

The heat release to the human body is determined with the help of the First Law of Thermodynamics:


-Q_(out) + U_(in) - U_(out) = 0


Q_(out) = U_(out) - U_(in)


Q_(out) = m\cdot c_(w)\cdot \Delta T


Q_(out) = (125\,g)\cdot \left(4.184\,(J)/(g\cdot ^(\textdegree)C) \right)\cdot (55^(\circ)C - 37^(\circ)C)


Q_(out) = 9414\,J

User Yuudachi
by
5.4k points