Answer:
The magnitude of the force F =
![- 2.363*10^(-5) \ \ N](https://img.qammunity.org/2021/formulas/physics/college/xdwt7obbrcsucskwuoaqjyktto5a0vmrqm.png)
The direction of the force is in opposite direction.
Step-by-step explanation:
The expression for force per unit length between two parallel wires carrying current
and
can be written as:
![F= (\mu_oI_1I_2)/(2 \pi a)](https://img.qammunity.org/2021/formulas/physics/college/p7no4838kv780c80ifyjuvlt3vq3h3md42.png)
permeability constant =
![4 \pi * 10 ^(-7) \ H/m](https://img.qammunity.org/2021/formulas/physics/college/msmwtldte61c51vt9nwyg5wc4d0sto0tzd.png)
a = distance between the wires = 4.00 cm = 0.04 cm
![I_2 = 3.15 \ A](https://img.qammunity.org/2021/formulas/physics/college/43comtn4qkhfpj82x4j5l45g7a766nmc0i.png)
replacing our values into the above equation; we have:
![F= (4 \pi*10^(-7)*1.5*3.15)/(2 \pi*0.04)](https://img.qammunity.org/2021/formulas/physics/college/rjq0yt6jirw3b8d5uo9w6pju6fqsxmctti.png)
![F = 2.363*10^(-5) \ \ N](https://img.qammunity.org/2021/formulas/physics/college/7i38moqrfa4y7epmzfelagp740zg7p3n8s.png)
Hence, If the current flows in the same direction, then , the force is said to be attractive (+ve) . However, if the direction of the current flow is opposite; then the force is said to be repulsive (-ve).
From the question given, the current flows in opposite direction in the wires, thus the force is said to be repulsive.
Thus ; F =
![- 2.363*10^(-5) \ \ N](https://img.qammunity.org/2021/formulas/physics/college/xdwt7obbrcsucskwuoaqjyktto5a0vmrqm.png)