Answer:
Step-by-step explanation:
Remark
The answer is in the formula
E = I * R
- E = the voltage
- I = the Current
- R = the Resistance
Solution
Let the resistance = R
I = 12/R
If we increase the resistance by 20% then we get
R1 = R + (20/100) * R
R1 = R + 1/5 * R
R1 = 6 R/5
What happens to I when you do this
I = 12/(6/5 R) Effectively you need to treat 6/5 as a reciprocal
I = 12 * 5/6 * R
I = 10 / R
What does this tell you? Since the Resistance has a base value of R, when increased by 20%, the numerator of the fraction is reduced to 10 from 12. In other words the current is now smaller when R goes up.