Answer:
The angle that the ramp forms with the ground is 27.5°
Explanation:
Check the attachment for the figure.
Using the SOH CAH TOA trigonometry identity
For TOA
Tan(theta) = opposite/adjacent
Given opposite = 1.3m(side facing the angle of inclination
Adjacent = bottom of the ramp= 2.5m
Tan(theta) = 1.3/2.5
Tan(theta) = 0.52
theta = arctan0.52
theta = 27.5°