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The Concentration of C6H12O6 May be represented as?

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4 votes

Answer:

Step-by-step explanation:

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M

User SeanOC
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2 votes

Answer:

A 12 oz Coca Cola contains 39g of sugar or C6H12O6.

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g/ 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M

Step-by-step explanation:

User Shriyog
by
4.5k points