Question

Find parametric equations for the line parallel to r = (6,-8) and passing through P (9, -1)

Answer 1

x=6t+9

y=-8t-1

Explanation:

That's what the show me video said

Answer 2

`x = (12-t)/(4)` and
`y = (t - 3)/(3)`

Explanation:

The slope of the line is:

`m = (-8-0)/(6-0)`

`m = -(4)/(3)`

The slope-intercept formula of the line is:

`y + 1 = -(4)/(3)\cdot (x - 9)`

`y + 1 = -(4)/(3)\cdot x +12`

A possible choice is:

`3\cdot y + 3 = -4 \cdot x + 12`

`t = 3\cdot y + 3 = -4\cdot x + 12`

`3\cdot y = t - 3`

`y = (t - 3)/(3)`

`-4\cdot x = t - 12`

`x = (12-t)/(4)`

The parametric equation for the line parallel to r = (6,-8) and passing through P (9, -1) is:

`x = (12-t)/(4)` and
`y = (t - 3)/(3)`