Find parametric equations for the line parallel to r = (6,-8) and passing through P (9, -1)

Question

asked Jun 23, 2021 20.3k views

2 Answers

Genzer · Answer 1 · 2021-06-28T01:53:52+0000

Answer:

x = (12-t)/(4) and
y = (t - 3)/(3)

Explanation:

The slope of the line is:

m = (-8-0)/(6-0)

m = -(4)/(3)

The slope-intercept formula of the line is:

$y + 1 = -(4)/(3)\cdot (x - 9)$

$y + 1 = -(4)/(3)\cdot x +12$

A possible choice is:

$3\cdot y + 3 = -4 \cdot x + 12$

$t = 3\cdot y + 3 = -4\cdot x + 12$

$3\cdot y = t - 3$

y = (t - 3)/(3)

$-4\cdot x = t - 12$

x = (12-t)/(4)

The parametric equation for the line parallel to r = (6,-8) and passing through P (9, -1) is:

x = (12-t)/(4) and
y = (t - 3)/(3)