Question

16. A dice game at a local carnival uses a 10-sided die which has been rigged. The even numbered outcomes (2, 4, 6, 8, and 10) have been made lighter so that they are three times more likely to occur as the odd numbered outcomes (1, 3, 5, 7, and 9). A player that rolls an odd number wins the game. What is the probability of winning this game?

Answer 1

1/4 or 0.25

Explanation:

Let x = probability of each of the odd numbered outcomes. Then the even numbered outcomes each have probability 3x. The sum of the probabilities is 1, so 5(3x) + 5(x) = 1, therefore 20x = 1 and x = 0.05. The probability of rolling an odd outcome (1, 3, 5, 7, or 9) each which have probability 0.05 is 5(0.05) = 0.25.

Answer 2

1/4 or 0.25

Explanation:

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