Question

I need help ASAP What is (g-f)(x)?

Answer 1

`-x^2-3x-6`

Explanation:

`(g-f)(x)` is simply the difference between the two functions
`g(x)` and
`f(x)`. If
`g(x)=-x^2-1-2x` and
`f(x)=x+5`, then

`(g-f)(x)=(-x^2-1-2x)-(x+5)\\(g-f)(x)=-x^2-1-2x-x-5\\(g-f)(x)=-x^2-3x-6`

Answer 2

Explanation:

g(x) = -x² - 1 - 2x

f(x) = x + 5

(g-f)(x) = g(x) - f(x)

(g-f)(x) = (-x² - 1 - 2x) - (x + 5)

(g-f)(x) = -x² - 2x - x - 1 - 5

(g-f)(x) = -x² - 3x - 6