Question

Given the following equation: 8Fe+S8=8FeS

a. If 4.2 moles of sulfur react, what is the mass of FeS produced?

b. if 13 moles of Fe react, what is the mass of FeS produced?

Answer 1

a. 2954g of FeS

b. 1143g of FeS

Step-by-step explanation:

Based on the reaction:

8 Fe + S₈ → 8 FeS

8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS

a. 4.2mol sulfur produce:

4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = 33.6mol FeS. As molar mass of FeS is 87.92g/mol, mass is:

33.6mol FeS × ( 87.92g / 1 mol FeS) = 2954g of FeS

b. 13mol Fe produce:

13mol Fe × ( 8 mol FeS / 8 mol Fe) = 13mol FeS. In mass:

13 mol FeS × ( 87.92g / 1 mol FeS) = 1143g of FeS