Question

If 1.178 mol of pure helium gas at 2.59 atm occupies a 10.50 L canister, what 1 point

is the temperature of the gas in degrees Celsius? *

Answer 1

The answer to your question is T = 281.5°K

Step-by-step explanation:

Data

number of moles = 1.178

pressure = 2.59 atm

volume = 10.5 l

temperature = ?

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Write the formula of ideal gases

PV = nRT

-Solve for T

T = PV / nR

2.- Substitution

T = (2.59 x 10.5) / (1.178 x 0.082)

3.- Simplification

T = 27.195 / 0.0966

4.- Result

T = 281.5°K