Question

A scalpel made of surgical stainless steel is sterilized by heating in a flame and then quenching in 175 g of ethyl alcohol. The alcohol is initially room temperature, 23.7°C, warms to 38.6°C. The specific heat capacity of ethyl alcohol is 2.4 J/(g*K) Assuming there is no heat lost to the surroundings, calculate the heat released by the alcohol.

Answer 1

I believe its -6300. I could be wrong though.

Step-by-step explanation:

The heat of a reaction may be found with the equation q=mcT

so if you want to find the answer you have to multiply

175 * 2.4 * 14.9 = 6258 or roughly 6300.

Since its asking how much heat is lost you have lost, you have to make it negative because there is no heat lost because the alcohol is gaining heat.